TR 4
30 m
2 E + F
5 10 19 π
2 n sin 38
2 n = 0 $$\partial t$$
2 d n 2x dx n = 1 3 [5 1 x^2 dx 2 0 2c 3 1 n + 2(2) 4π^2 R n J + (n = 1 F = m 2 1 8 $$\Delta V + h = \frac{1}{4} \times \left($$ + 242 72 2 + √82 b ± 3! 2a qU 2 $cV^2$
30 m
2 E + F
5 10 19 π
2 n sin 38
2 n = 0 $$\partial t$$
2 d n 2x dx n = 1 3 [5 1 x^2 dx 2 0 2c 3 1 n + 2(2) 4π^2 R n J + (n = 1 F = m 2 1 8 $$\Delta V + h = \frac{1}{4} \times \left($$ + 242 72 2 + √82 b ± 3! 2a qU 2 $cV^2$
这表盘高数学霸看了都头疼吧
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