穿这个进得去考场?

$$=\frac{1}{2} S_{10}$$
v
v
$$x^{\prime}+1\leq 2^{\prime}=16$$ 8
$$\begin{align*}&(2a_3/4)\\ &+\frac{1}{2}(A_2)=\left|\begin{array}{l}10\,2.5\\ 2.5\\ 0\end{array}\right|\end{align*}$$
10
0
$$y_{10} 2\sqrt{5}|$$
$$\times G$$
$$=\frac{y_1}{(A_2)}=\frac{y_1}{|2\sqrt{2}|2\sqrt{2}|}$$
$$\frac{y!}{8}\leq 4$$
$$F_0=5^{\circ}\pi$$
$$\omega_{1}=m(1)/ 4\sin x(1)/ 4$$
$$F_0=5^{\circ}\frac{1}{4}\sum_{m=1}^{\circ}\frac{1}{4$$
$$S_{a}=S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime}=\frac{1}{2} S_{a}^{\prime$$
$$u\sqrt{\frac{1}{2}}$$
$$A B=AC$$ $$Q=mC O_1$$
$$M=\cos\phi$$
cAB1OB
$$\frac{1}{8}=\frac{1}{4}\sum_{n=1}^{n}\frac{1}{8}$$
$$\text{ by} x\cdot\text{ cotg} x=1$$
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